Solve by Element List Regression
Determining Coefficients of a Polynomial on the SAT: Desmos Walkthrough
This lesson uses sliders and direct evaluation in Desmos: put the unknown constant on a slider or a single expression line and let the calculator find the value instead of solving algebra by hand.
Take this lesson interactivelyA real SAT-style question
In the xy-plane, a parabola has vertex and intersects the x-axis at two points. If the equation of the parabola is written in the form , where , , and are constants, which of the following could be the value of ?
How to solve it in Desmos, step by step
The idea
Use vertex form so the vertex (9, negative 14) is built in, add a slider for a, then set a to a positive value that makes the curve cross the x-axis twice and have Desmos read off a plus b plus c.
- 1
Step 1
Type the vertex form using the vertex (9, negative 14). Desmos pops up an Add Slider button for a, so tap it to create the a slider.Type in Desmos
- 2
Step 2
Set the a slider to a positive number so the parabola opens upward and crosses the x-axis at two points, which is the condition the question requires. A negative a would open downward and miss the axis. Set a to 1 over 32 by typing this line.Type in Desmos
- 3
Step 3
Add this line to display a plus b plus c. Expanding a times (x minus 9) squared minus 14 gives a, then negative 18 a, then 81 a minus 14, which sum to 64 a minus 14. With a at 1 over 32 Desmos shows the value negative 12, matching choice D. Because a must stay positive, 64 a minus 14 is always greater than negative 14, so the other choices are impossible.Type in Desmos
The answer is D.
Now you try one
Same question type, different numbers. Use the exact Desmos moves from the walkthrough above.
Practice this with a live Desmos calculator
The interactive version of this lesson builds the Desmos graph up step by step as you click through, with a live calculator you can type into and your progress saved.
Open the interactive lesson